Quiz Discussion

A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

Course Name: Quantitative Aptitude

• 1] 45
• 2] 60
• 3] 75
• 4] 90
• 5] None of these
Solution
No Solution Present Yet

Top 5 Similar Quiz - Based On AI&ML

Quiz Recommendation System API Link - https://fresherbell-quiz-api.herokuapp.com/fresherbell_quiz_api

# Quiz
1
Discuss

52 + 132  – 112 = (?)3 – 52

• 1]

6

• 2]

3

• 3]

4

• 4]

5

Solution
2
Discuss

If $$\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}$$     then the value of $$\left( {{a^3} + \frac{1}{{{a^3}}}} \right)$$   is = ?

• 1] 198
• 2] 200
• 3] 216
• 4] None of these
Solution
3
Discuss

The value of x in the equation  = 5     is?

• 1] 21
• 2] 27
• 3] 35
• 4] 42
Solution
4
Discuss

$$\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?$$

• 1]

6/49

• 2]

6/11

• 3]

3/28

• 4]

1/7

• 5]

None of these

Solution
5
Discuss

If $$\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1$$     and $$\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0$$     where a, b, c, p, q, r are non-zero real numbers, then $$\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}$$    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9
Solution
6
Discuss

$${ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?$$

• 1]

2/5

• 2]

5/2

• 3]

3/5

• 4]

1/2

Solution
7
Discuss

If $$\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}}$$    then $$\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)$$   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5
Solution
8
Discuss

Simplify : $${ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]$$

• 1]

$$4\frac{1}{2}$$

• 2]

$$4\frac{1}{6}$$

• 3]

$$9\frac{1}{2}$$

• 4]

$$\frac{2}{9}$$

Solution
9
Discuss

The value of $${ \text{3}}\frac{1}{2} - \left[ {2\frac{1}{4} \div \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]$$       = ?

• 1]

1/2

• 2]

$$2\frac{1}{2}$$

• 3]

$$3\frac{1}{2}$$

• 4]

$$9\frac{1}{2}$$

Solution
10
Discuss

The Value of ($$\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}$$) = ?

• 1] 27
• 2] 18
• 3] 40
• 4] 10
# Quiz