# Quiz Discussion

Number of digits in the square root of 62478078 is = ?

Course Name: Quantitative Aptitude

• 1] 4
• 2] 5
• 3] 6
• 4] 3
##### Solution
No Solution Present Yet

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# Quiz
1
Discuss

5907 – 1296 / 144 = x * 8.0

• 1]

700.05

• 2]

705.25

• 3]

751.54

• 4]

737.25

##### Solution
2
Discuss

If a - b = 3 and a2 + b2 = 29, find the value of ab = ?

• 1] 10
• 2] 12
• 3] 15
• 4] 18
##### Solution
3
Discuss

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these
##### Solution
4
Discuss

(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55

• 1] 2254
• 2] 2354
• 3] 2368
• 4] 2404
• 5] None of these
##### Solution
5
Discuss

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

• 1] 770
• 2] 1155
• 3] 1540
• 4] (385)2
##### Solution
6
Discuss

If 45 - [28 - {37 - (15 - *)}]  then * equal to?

• 1] -29
• 2] -19
• 3] 19
• 4] 29
##### Solution
7
Discuss

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

• 1] 20
• 2] 80
• 3] 100
• 4] 200
• 5] None of these
##### Solution
8
Discuss

$$6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?$$

• 1]

$$112\frac{1}{3}$$

• 2]

$$116\frac{2}{3}$$

• 3]

240

• 4]

663

• 5]

None of these

##### Solution
9
Discuss

$${ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?$$

• 1]

2/5

• 2]

5/2

• 3]

3/5

• 4]

1/2

##### Solution
10
Discuss

Simplify : $$\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?$$

• 1]

100/101

• 2]

90/101

• 3]

20/101

• 4]

101/100

# Quiz