The value of \(\frac{{{{\left( {0.96} \right)}^3} - {{\left( {0.1} \right)}^3}}}{{{{\left( {0.96} \right)}^2} + 0.096 + {{\left( {0.1} \right)}^2}}}{ \text{is}}:\)
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1
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The value of (1.25)3 - 2.25 (1.25)2 + 3.75 (0.75)2 - (0.75)3 is :
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2
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3889 + 12.952 - ? = 3854.002
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3
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Which part contains the fractions in ascending order ?
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4
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When 0.232323..... is converted into a fraction, then the result is:
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5
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The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
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6
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\(\frac{{\left( {0.1667} \right)\left( {0.8333} \right)\left( {0.3333} \right)}}{{\left( {0.2222} \right)\left( {0.6667} \right)\left( {0.1250} \right)}}\) is approximately equal to:
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7
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58.621 - 13.829 - 7.302 - 1.214 = ?
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8
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Solution |
9
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Out of the fractions 9/31, 3/17, 6/23, 4/11, and 7/25 which is the largest?
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10
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The place value of 9 in 0.06945 is :
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