# Quiz Discussion

Which of the following are in descending order of their value ?

Course Name: Quantitative Aptitude

• 1]

$$\frac{1}{3},\frac{2}{5},\frac{3}{7},\frac{4}{5},\frac{5}{6},\frac{6}{7}$$

• 2]

$$\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{7},\frac{5}{6},\frac{6}{7}$$

• 3]

$$\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{6},\frac{5}{7},\frac{6}{7}$$

• 4]

$$\frac{6}{7},\frac{5}{6},\frac{4}{5},\frac{3}{7},\frac{2}{5},\frac{1}{3}$$

##### Solution
No Solution Present Yet

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# Quiz
1
Discuss

The place value of 9 in 0.06945 is :

• 1]

9

• 2]

9/10

• 3]

9/100

• 4]

9/1000

##### Solution
2
Discuss

Solve : $$7\frac{1}{2} - \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]$$       = ?

• 1]

2/9

• 2]

$$4\frac{1}{2}$$

• 3]

$$9\frac{1}{2}$$

• 4]

$$1\frac{77}{228}$$

##### Solution
3
Discuss

$$\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?$$ = ?

• 1] 0.002
• 2] 0.020
• 3] 0.021
• 4] 0.023
##### Solution
4
Discuss

3889 + 12.952 - ? = 3854.002

• 1] 47.095
• 2] 47.752
• 3] 47.932
• 4] 47.95
##### Solution
5
Discuss

When 52416 is divided by 312, the quotient is 168. What will be the quotient when 52.416 is divided by 0.0168 ?

• 1] 3.12
• 2] 312
• 3] 3120
• 4] None of these
##### Solution
6
Discuss

Solve this, (3.5 × 1.4)/ 0.7  = ?

• 1] 0.7
• 2] 2.4
• 3] 3.5
• 4] 7.1
• 5] None of these
##### Solution
7
Discuss

If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?

• 1] 0.172
• 2] 1.72
• 3] 17.2
• 4] 172
##### Solution
8
Discuss

The expression (11.98 × 11.98 + 11.98 × X + 0.02 × 0.02) will be a perfect square for X equal to:

• 1] 0.02
• 2] 0.2
• 3] 0.04
• 4] 0.4
##### Solution
9
Discuss

Given, 168 × 32 = 5376 , then 5.376 ÷ 16.8 is equal to :

• 1] 0.032
• 2] 0.32
• 3] 3.2
• 4] 32
##### Solution
10
Discuss

How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

• 1] 5
• 2] 6
• 3] 7
• 4] None of these
# Quiz