If the sums of n terms of two arithmetic progressions are in the ratio \(\frac{{3n + 5}}{{5n + 7}}\) then their nth terms are in the ration
\(\frac{{3n - 1}}{{5n - 1}}\)
\(\frac{{3n + 1}}{{5n + 1}}\)
\(\frac{{5n + 1}}{{3n + 1}}\)
\(\frac{{5n - 1}}{{3n - 1}}\)
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2
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3
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4
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5
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7
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8
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9
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