Quiz Discussion

A square is drawn by joining the mid points of the sides of a given square in the same way and this process continues indefinitely. If a side of the first square is 4 cm, determine the sum of the areas all the square.

Course Name: Quantitative Aptitude

  • 1] 32 Cm2
  • 2] 16 Cm2
  • 3] 20 Cm2
  • 4] 64 Cm2
  • 5] None of these
Solution
No Solution Present Yet

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# Quiz
1
Discuss

If 7 times the seventh term of an Arithmetic Progression (AP) is equal to 11 times its eleventh term, then the 18th term of the AP will be

  • 1] 0
  • 2] 1
  • 3] 2
  • 4] -1
Solution
2
Discuss

What is the sum of the first 9 terms of an arithmetic progression if the first term is 7 and last term is 55?

  • 1] 219
  • 2] 279
  • 3] 231
  • 4] 137
Solution
3
Discuss

The sum of the first and third term of an arithmetic progression is 12 and the product of first and second term is 24, then first term is

  • 1]

    4

  • 2]

    1

  • 3]

    8

  • 4]

    6

Solution
4
Discuss

If an A.P. has a = 1, tn = 20 and sn = 399, then value of n is :

  • 1] 20
  • 2] 32
  • 3] 38
  • 4] 40
Solution
5
Discuss

The 7th and 12th term of an arithmetic progression are -15 and 5 respectively. What is the 16th term?

  • 1] 25
  • 2] 29
  • 3] 21
  • 4] 33
Solution
6
Discuss

The first term of an Arithmetic Progression is 22 and the last term is -11. If the sum is 66, the number of terms in the sequence are:

  • 1]

    9

  • 2]

    10

  • 3]

    11

  • 4]

    12

Solution
7
Discuss

In an A.P., if d = -4, n = 7, an = 4, then a is

  • 1]

    6

  • 2]

    7

  • 3]

    20

  • 4]

    28

Solution
8
Discuss

What is the sum of the first 11 terms of an arithmetic progression if the 3rd term is -1 and the 8th term is 19?

  • 1] 204
  • 2] 121
  • 3] 225
  • 4] 104
Solution
9
Discuss

The common difference of the A.P. \(\frac{1}{{2b}} \frac{{1 - 6b}}{{2b}}  \frac{{1 - 12b}}{{2b}}\)   . . . . . is

 

  • 1] 2b
  • 2] -2b
  • 3] 3
  • 4] -3
Solution
10
Discuss

The common difference of the A.P. \(\frac{1}{3}, \frac{{1 - 3b}}{3} , \frac{{1 - 6b}}{3}\)   . . . . . . is

 

  • 1]

    \(\frac{1}{3}\)

  • 2]

    \( - \frac{1}{3}\)

  • 3]

    -b

  • 4]

    b

Solution
# Quiz