Quiz Discussion

If the fifth term of a GP is 81 and first term is 16, what will be the 4th term of the GP?

Course Name: Quantitative Aptitude

  • 1] 36
  • 2] 18
  • 3] 54
  • 4] 24
  • 5] 27
Solution
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# Quiz
1
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(\frac{{n\left( {n - 1} \right)}}{2}\)

  • 3]

    \({n^2}\)

  • 4]

    n

Solution
2
Discuss

Two A.P.’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 30th terms is

  • 1] 11
  • 2] 3
  • 3] 8
  • 4] 5
Solution
3
Discuss

The common difference of the A.P. \(\frac{1}{{2b}} \frac{{1 - 6b}}{{2b}}  \frac{{1 - 12b}}{{2b}}\)   . . . . . is

 

  • 1] 2b
  • 2] -2b
  • 3] 3
  • 4] -3
Solution
4
Discuss

Find the nth term of the following sequence :

  • 1]

    5(10n - 1)

  • 2]

    5n(10n - 1)

  • 3]

    \(\frac{5}{9} \times \left( {{{10}^n} - 1} \right)\)

  • 4]

    \({\left( {\frac{5}{9}} \right)^n} \times \left( {{{10}^n} - 1} \right)\)

Solution
5
Discuss

The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is

  • 1]

    5

  • 2]

    10

  • 3]

    12

  • 4]

    14

Solution
6
Discuss

How many terms are there in the GP 5, 20, 80, 320........... 20480?

  • 1] 5
  • 2] 6
  • 3] 8
  • 4] 9
  • 5] 7
Solution
7
Discuss

15th term of A.P., x - 7, x - 2, x + 3, ........ is

  • 1] x + 63
  • 2] x + 73
  • 3] x + 83
  • 4] x + 53
Solution
8
Discuss

What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?

  • 1]

    897

  • 2]

    1,64,850

  • 3]

    1,64,749

  • 4]

    1,49,700

Solution
9
Discuss

If the sum of the series 2 + 5 + 8 + 11 … is 60100, then the number of terms are

  • 1]

    100

  • 2]

    150

  • 3]

    200

  • 4]

    250

Solution
10
Discuss

If an A.P. has a = 1, tn = 20 and sn = 399, then value of n is :

  • 1] 20
  • 2] 32
  • 3] 38
  • 4] 40
Solution
# Quiz