Quiz Discussion

If = the value of x is = ?

 

Course Name: Quantitative Aptitude

  • 1] 52
  • 2] 58
  • 3] 62
  • 4] 68
Solution
No Solution Present Yet

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# Quiz
1
Discuss

If \(x = 3 + \sqrt 8 ,   \) then \({x^2} + \frac{1}{{{x^2}}}\) is equal to = ?

 

  • 1] 30
  • 2] 34
  • 3] 36
  • 4] 38
Solution
2
Discuss

\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} -   \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} +   \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} -   \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} +   \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\)   is equal to ?

 

  • 1]

    0

  • 2]

    1/3

  • 3]

    1

  • 4]

    5

Solution
3
Discuss

In the equation \(\frac{{4050}}{{\sqrt x }} = 450{ \text{}}\)   the value of x is = ?

 

  • 1] 9
  • 2] 49
  • 3] 81
  • 4] 100
Solution
4
Discuss

The approximate value of \(\frac{{3\sqrt {12} }}{{2\sqrt {28} }} \div \frac{{2\sqrt {21} }}{{\sqrt {98} }}\)  is ?

 

  • 1] 1.0605
  • 2] 1.0727
  • 3] 1.6007
  • 4] 1.6026
Solution
5
Discuss

Find the cube root of 2744.

  • 1]

    14

  • 2]

    13

  • 3]

    12

  • 4]

    11

Solution
6
Discuss

Determined the value of \(\frac{1}{{\sqrt 1 + \sqrt 2 }}{ \text{ + }}  \frac{1}{{\sqrt 2 + \sqrt 3 }} +   \frac{1}{{\sqrt 3 + \sqrt 4 }} +   ...... +   \frac{1}{{\sqrt {120} + \sqrt {121} }}{ \text{ = ?}}\)

 

  • 1]

    8

  • 2]

    10

  • 3]

    \(\sqrt {120} \)

  • 4]

    \(12\sqrt 2 \)

Solution
7
Discuss

One-fourth of the sum of prime numbers, greater than 4 but less than 16, is the square of = ?

  • 1] 3
  • 2] 4
  • 3] 5
  • 4] 7
Solution
8
Discuss

The square root of 64009 is:

  • 1] 253
  • 2] 347
  • 3] 363
  • 4] 803
Solution
9
Discuss

\(\sqrt {1.5625} = ?\)

 

  • 1] 1.05
  • 2] 1.25
  • 3] 1.45
  • 4] 1.55
Solution
10
Discuss

\(99 \times 21 - \root 3 \of ? = 1968\)

 

  • 1] 1367631
  • 2] 111
  • 3] 1366731
  • 4] 1367
Solution
# Quiz