\(99 \times 21 - \root 3 \of ? = 1968\)
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\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} - \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} + \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} - \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} + \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\) is equal to ?
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\({\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}\) simplifies to:
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1250 oranges were distributed among a group of girls of a class. Each girl got twice as many oranges as the number of girls in that group. The number of girls in the group was = ?
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If \(x = \frac{{\sqrt 3 + 1}}{{\sqrt 3 - 1}} \) \(y = \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}\)and then the value of \(\left( {{x^2} + {y^2}} \right)\) is?
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If \({ \text{ }}2*3 = \sqrt {13} \) and 3 * 4 = 5, then the value of 5 * 12 is ?
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If \(\sqrt {24} = 4.889,\) the value of \(\sqrt {\frac{8}{3}} \) is = ?
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Solved \( \root 4 \of {{{\left( {625} \right)}^3}} = ?\)
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If \(\sqrt 5 = 2.236, \) then the value of \(\frac{{\sqrt 5 }}{2} - \frac{{10}}{{\sqrt 5 }} + \sqrt {125} \) is equal to :
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While solving a mathematical problem, Samidha squared a number and then subtracted 25 from it rather than the required i.e., first subtracting 25 from the number and then squaring it. But she got the right answer. What was the given number ?
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