\(\sqrt {\frac{{16}}{{25}}} \times \sqrt {\frac{?}{{25}}} \times \frac{{16}}{{25}} = \frac{{256}}{{625}}\)
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While solving a mathematical problem, Samidha squared a number and then subtracted 25 from it rather than the required i.e., first subtracting 25 from the number and then squaring it. But she got the right answer. What was the given number ?
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2
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The square root of 64009 is:
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3
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How many two-digit numbers satisfy this property. : The last digit (unit's digit) of the square of the two-digit number is 8 ?
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4
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What percentage of the numbers from 1 to 50 have squares that end in the digit 1 ?
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5
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The value of \(\sqrt {0.000441} \) is = ?
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6
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Find the square root of 3 upto three decimal places
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7
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For what value of * the statement
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8
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\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} - \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} + \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} - \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} + \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\) is equal to ?
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9
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If x=
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10
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The value of \(\sqrt {0.01} { \text{ + }} \sqrt {0.81} { \text{ + }} \sqrt {1.21} { \text{ + }} \sqrt {0.0009} \) is = ?
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