Quiz Discussion

The value of \(\frac{{489.1375 \times 0.0483 \times 1.956}}{{0.0873 \times 92.581 \times 99.749}}\)     is closest to:

• 1] 0.006
• 2] 0.06
• 3] 0.6
• 4] 6

34.95 + 240.016 + 23.98 = ?

• 1] 298.0946
• 2] 298.111
• 3] 298.946
• 4] 299.09

\(\frac{{.009}}{?} = .01\)

• 1] .0009
• 2] .09
• 3] .9
• 4] 9

If 47.2506=4A+7/B+2C+5/D +6E then the value of 5A+3B+6C+D+3E is

• 1]

  53.6003

• 2]

  53.603

• 3]

  153.6003

• 4]

  213.003

3889 + 12.952 - ? = 3854.002

• 1] 47.095
• 2] 47.752
• 3] 47.932
• 4] 47.95

47.7 × 12.4 × 8.6 = ?

• 1] 5086.728
• 2] 5218.668
• 3] 5708.428
• 4] 6180.656
• 5] None of these

58.621 - 13.829 - 7.302 - 1.214 = ?

• 1] 31.254
• 2] 35.272
• 3] 36.276
• 4] 37.281
• 5] None of these

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1] 2010
• 2] 2011
• 3] 2012
• 4] 2013

Solve : \(7\frac{1}{2} -  \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)       = ?

• 1]

  2/9

• 2]

  \(4\frac{1}{2}\)

• 3]

  \(9\frac{1}{2}\)

• 4]

  \(1\frac{77}{228}\)

Solve this, (3.5 × 1.4)/ 0.7  = ?

• 1] 0.7
• 2] 2.4
• 3] 3.5
• 4] 7.1
• 5] None of these