There are 20 people among whom two are sisters. Find the number of ways in which we can arrange them around a circle so that there is exactly one person between the two sisters.
2! x 19!
18!
18! x 2!
19!
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1
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In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
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2
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A biased coin in tossed thrice. What is the probability that heads turns out at least twice considering that the probability of a head is 60%?
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3
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In how many ways the letters of the word “UNDERDOG” can be arranged such that the first and last letters are same and no two vowels are together?
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4
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Seven different objects must be divided among three people. In how many ways can this be done if one or two of them must get no objects?
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5
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Find the probability that a leap year selected at random will contain 53 Sundays
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6
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Four letters are selected from the word “CAPAME” and are rearranged to form four letter words. How many words can be formed?
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7
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How many natural numbers can be made with digits 0, 7, 8 which are greater than 0 and less than a million?
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8
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A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?
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9
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The value of 75P2
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10
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A person tosses an unbiased coin. When head turns up, he gets Rs.8 and tail turns up he loses Rs.4. If 3 coins are tossed, what is probability that he gets a profit of Rs.12?
SolutionPerson will get profit of Rs 12 only when there is 2H (Head) and 1T (Tail) H + H + T = 12 8 + 8 + (-4) = 12 Total outcome of 2 head and 1 tail = 23 = 8 i.e (T, H, TH, HT, HH, HHT, HTH, THH) Total event with 2H and 1 T is 3 therfore probability = 3/8 |
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