Quiz Discussion

In how many ways the letters of the word “UNDERDOG” can be arranged such that the first and last letters are same and no two vowels are together?

Course Name: Quantitative Aptitude

  • 1]

    72

  • 2]

    96

  • 3]

    132

  • 4]

    144

  • 5]

    None of these

Solution
No Solution Present Yet

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# Quiz
1
Discuss

How many words, with or without meaning, can be formed using all letters of the word EQUATION using each letter exactly once?

  • 1]

    38,320

  • 2]

    39,320

  • 3]

    38,400

  • 4]

    40,320

Solution
2
Discuss

There are 6 letters for 3 envelopes. In how many different ways can the envelopes be filled?

  • 1]

    120

  • 2]

    130

  • 3]

    100

  • 4]

    110

Solution
3
Discuss

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated

  • 1]

    5

  • 2]

    10

  • 3]

    15

  • 4]

    20

Solution
4
Discuss

How many natural numbers can be made with digits 0, 7, 8 which are greater than 0 and less than a million?

  • 1]

    496

  • 2]

    728

  • 3]

    486

  • 4]

    1084

Solution
5
Discuss

If A and B are two independent events with P(A) = 3/5 and P(B) = 4/9 , then P(A' ∩ B' ) equals

  • 1]

    4/15

  • 2]

    8/45

  • 3]

    1/3

  • 4]

    2/9

Solution
6
Discuss

A box contains 5 green, 4 yellow and 3 white marbles. three marbles are drawn at random. What is the probability that all they are not of the same colour?

  • 1]

    3/44

  • 2]

    3/55

  • 3]

    52/55

  • 4]

    41/44

Solution
7
Discuss

A teacher has to choose the maximum different groups of three students from a total of six students. Of these groups, in how many groups there will be included in a particular student?

  • 1]

    12

  • 2]

    10

  • 3]

    8

  • 4]

    6

Solution
8
Discuss

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

  • 1]

    159

  • 2]

    194

  • 3]

    205

  • 4]

    209

Solution
9
Discuss

There are 8 orators A, B, C, D, E, F, G, and H. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.

  • 1]

    8! / 3!

  • 2]

    8! / 6!

  • 3]

    5! x 3!

  • 4]

    8! / (5! x 3!) 

Solution
10
Discuss

If (n + 2)! = 2550 (n!); find ’n’

  • 1]

    49

  • 2]

    35

  • 3]

    38

  • 4]

    43

Solution
# Quiz