Quiz Discussion

The square root of (2722−1282) is

Course Name: Quantitative Aptitude

  • 1]

    144

  • 2]

    200

  • 3]

    240

  • 4]

    256

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If x=.and y= find value of  is

  • 1]

    13

  • 2]

    14

  • 3]

    15

  • 4]

    16

Solution
2
Discuss

If the product of four consecutive natural numbers increased by a natural number p, is a perfect square, then the value of p is = ?

  • 1] 1
  • 2] 2
  • 3] 4
  • 4] 8
Solution
3
Discuss

Which number can replace both the question marks in the equation =?

 

  • 1]

    12

  • 2]

    7

  • 3]

  • 4]

    None of these

Solution
4
Discuss

\(\sqrt {\frac{{16}}{{25}}} \times \sqrt {\frac{?}{{25}}} \times \frac{{16}}{{25}} = \frac{{256}}{{625}}\)

 

  • 1] 5
  • 2] 8
  • 3] 16
  • 4] None of these
Solution
5
Discuss

If 1537* is a perfect square, then the digit which replace * is = ?

  • 1] 2
  • 2] 4
  • 3] 5
  • 4] 6
Solution
6
Discuss

\(99 \times 21 - \root 3 \of ? = 1968\)

 

  • 1] 1367631
  • 2] 111
  • 3] 1366731
  • 4] 1367
Solution
7
Discuss

\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} -   \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} +   \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} -   \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} +   \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\)   is equal to ?

 

  • 1]

    0

  • 2]

    1/3

  • 3]

    1

  • 4]

    5

Solution
8
Discuss

The square root of 64009 is:

  • 1] 253
  • 2] 347
  • 3] 363
  • 4] 803
Solution
9
Discuss

The square root of 535.9225 is = ?

  • 1] 23.15
  • 2] 23.45
  • 3] 24.15
  • 4] 28.25
Solution
10
Discuss

If \(a = \frac{{\sqrt 3 }}{2}{ \text{}}\)   then \(\sqrt {1 + a} + \sqrt {1 - a} = ?\)

 

  • 1]

    \(\left( {2 - \sqrt 3 } \right)\)

  • 2]

    \(\left( {2 + \sqrt 3 } \right)\)

  • 3]

    \(\left( {\frac{{\sqrt 3 }}{2}} \right)\)

  • 4]

    \(\sqrt 3 \)

Solution
# Quiz