Quiz Discussion

If x=.and y= find value of  is

• 1]

  13

• 2]

  14

• 3]

  15

• 4]

  16

If the product of four consecutive natural numbers increased by a natural number p, is a perfect square, then the value of p is = ?

• 1] 1
• 2] 2
• 3] 4
• 4] 8

Which number can replace both the question marks in the equation =?

• 1]

  12

• 2]

  7

• 3]

  

• 4]

  None of these

\(\sqrt {\frac{{16}}{{25}}} \times \sqrt {\frac{?}{{25}}} \times \frac{{16}}{{25}} = \frac{{256}}{{625}}\)

• 1] 5
• 2] 8
• 3] 16
• 4] None of these

If 1537* is a perfect square, then the digit which replace * is = ?

• 1] 2
• 2] 4
• 3] 5
• 4] 6

\(99 \times 21 - \root 3 \of ? = 1968\)

• 1] 1367631
• 2] 111
• 3] 1366731
• 4] 1367

\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} -   \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} +   \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} -   \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} +   \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\)   is equal to ?

• 1]

  0

• 2]

  1/3

• 3]

  1

• 4]

  5

The square root of 64009 is:

• 1] 253
• 2] 347
• 3] 363
• 4] 803

The square root of 535.9225 is = ?

• 1] 23.15
• 2] 23.45
• 3] 24.15
• 4] 28.25

If \(a = \frac{{\sqrt 3 }}{2}{ \text{}}\)   then \(\sqrt {1 + a} + \sqrt {1 - a} = ?\)

• 1]

  \(\left( {2 - \sqrt 3 } \right)\)

• 2]

  \(\left( {2 + \sqrt 3 } \right)\)

• 3]

  \(\left( {\frac{{\sqrt 3 }}{2}} \right)\)

• 4]

  \(\sqrt 3 \)