The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
2010
2011
2012
2013
Quiz Recommendation System API Link  https://fresherbellquizapi.herokuapp.com/fresherbell_quiz_api
#  Quiz 

1
Discuss

4.036 divided by 0.04 gives :
Solution 
2
Discuss

617 + 6.017 + 0.617 + 6.0017 = ?
Solution 
3
Discuss

The sum of is
Solution 
4
Discuss

Which of the following fractions lies between 2/3 and 3/5 = ?
Solution 
5
Discuss

Out of the fractions 9/31, 3/17, 6/23, 4/11, and 7/25 which is the largest?
Solution 
6
Discuss

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
Solution 
7
Discuss

The value of \(\frac{{3.157 \times 4126 \times 3.198}}{{63.972 \times 2835.121}}\) is closest to :
Solution 
8
Discuss

The value of (1.25)^{3}  2.25 (1.25)^{2} + 3.75 (0.75)^{2}  (0.75)^{3} is :
Solution 
9
Discuss

Express 1999/2111 in decimal :
Solution 
10
Discuss

Find the value of the following expression upto four places of decimals. \(\left[ {1 + \frac{1}{{1 \times 2}} + \frac{1}{{1 \times 2 \times 4}} + \frac{1}{{1 \times 2 \times 4 \times 8}} + \frac{1}{{1 \times 2 \times 4 \times 8 \times 16}}} \right]\)
Solution 
#  Quiz 
Copyright © 2020 Inovatik  All rights reserved