Quiz Discussion

What number must be added to the expression 16a2 - 12a to make a perfect square ?

Course Name: Java

  • 1]

    9/4

  • 2]

    11/2

  • 3]

    13/2

  • 4]

    16

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If a*b= ab/a+b, find the value of 3*(3*-1)

  • 1]

    -1

  • 2]

    1

  • 3]

    3

  • 4]

    -3

Solution
2
Discuss

The simplest value of \(\left( {\frac{1}{{\sqrt 9 - \sqrt 8 }} - \frac{1}{{\sqrt 8 - \sqrt 7 }} + \frac{1}{{\sqrt 7 - \sqrt 6 }} - \frac{1}{{\sqrt 6 - \sqrt 5 }}} \right)\)          is = ?

 

  • 1]

    \(3 - \sqrt 5 \)

  • 2]

    3

  • 3]

    \(\sqrt 5 \)

  • 4]

    \(\sqrt 5 - 3\)

Solution
3
Discuss

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

 

  • 1] 2
  • 2] 8
  • 3] 18
  • 4] None of these
Solution
4
Discuss

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

 

  • 1] 0
  • 2] 1
  • 3] 3
  • 4] 9
Solution
5
Discuss

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

 

  • 1] 1
  • 2] 4
  • 3] 3
  • 4] 2
Solution
6
Discuss

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

 

  • 1]

    \({ \text{5}}\frac{1}{{10}}\)

  • 2]

    \({ \text{2}}\frac{1}{{18}}\)

  • 3]

    \({ \text{3}}\frac{1}{6}\)

  • 4]

    \({ \text{3}}\frac{3}{{10}}\)

Solution
7
Discuss

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

 

  • 1]

    1/2

  • 2]

    4

  • 3]

    2

  • 4]

    1/4

Solution
8
Discuss

Let 0 < x < 1, then the correct inequality is = ?

  • 1]

    \(x < \sqrt x < {x^2}\)

  • 2]

    \(\sqrt x < x < {x^2}\)

  • 3]

    \({x^2} < x < \sqrt x \)

  • 4]

    \(\sqrt x < {x^2} < x\)

Solution
9
Discuss

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

 

  • 1] -1
  • 2] 0
  • 3] 1
  • 4] None of these
Solution
10
Discuss

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

  • 1] -4
  • 2] 2
  • 3] 0
  • 4] 2
Solution
# Quiz