Quiz Discussion

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

Let 0 < x < 1, then the correct inequality is = ?

• 1]

  \(x < \sqrt x < {x^2}\)

• 2]

  \(\sqrt x < x < {x^2}\)

• 3]

  \({x^2} < x < \sqrt x \)

• 4]

  \(\sqrt x < {x^2} < x\)

If a - b = 3 and a2 + b2 = 29, find the value of ab = ?

• 1] 10
• 2] 12
• 3] 15
• 4] 18

The value of x in the equation  = 5     is?

• 1] 21
• 2] 27
• 3] 35
• 4] 42

98643 – 21748 = 51212 + ?

• 1]

  24383

• 2]

  24713

• 3]

  25683

• 4]

  26243

1559.95 - 7.99 × 24.96 - ?2 = 1154

• 1] 14
• 2] 24
• 3] 32
• 4] 18
• 5] 8

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100