Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)
0.006
1/6
0.6
6
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1
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Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \) = (?)3 + 141
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2
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\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \) is equal to = ?
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3
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\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\) is equal to = ?
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4
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(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?
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5
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25 * 3.250 + 50.40 / 24.0 = ?
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6
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On simplification the value of \({ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }} \frac{1}{{1 - \sqrt 2 }}\) is = ?
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7
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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8
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One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?
Solution |
9
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The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)
Solution |
10
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\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)
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