If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\) and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\) where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\) is equal to = ?
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Evaluate : \({{ - {{\left( {4 - 6} \right)}^2} - 3\left( { - 2} \right) + \left| { - 6} \right|} \over {18 - 9 \div 3 \times 5}}\)
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(4 / 5) × ? × (3 / 7) = (16 / 105)
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\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\) is equal to = ?
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Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.
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What is \(\frac{{\frac{7}{8} \times \frac{7}{8} + \frac{5}{6} \times \frac{5}{6} + \frac{7}{8} \times \frac{5}{3}}}{{\frac{7}{8} \times \frac{7}{8} - \frac{5}{6} \times \frac{5}{6}}}\) equal to ?
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If \(\left( {x - \frac{1}{x}} \right){ \text{ = }}\sqrt {21} { \text{,}} \) then the value of \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right) \left( {x + \frac{1}{x}} \right)\) is = ?
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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
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When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?
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If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \) then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\) = ?
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\(\sqrt {0.00060516} \) is equal to = ?
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