Quiz Discussion

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

• 1] 969
• 2] 1785
• 3] 980
• 4] 1700

24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?

• 1] 884
• 2] 346
• 3] 252
• 4] 424
• 5] 366

The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?

• 1] 27
• 2] 18
• 3] 40
• 4] 10

5² + 13²  – 11² = (?)³ – 52

• 1]

  6

• 2]

  3

• 3]

  4

• 4]

  5

(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?

• 1]

  5.5

• 2]

  4.0

• 3]

  4.5

• 4]

  3.0

Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)

• 1]

  \(8\frac{1}{5}\)

• 2]

  \(9\frac{1}{2}\)

• 3]

  \(11\frac{1}{2}\)

• 4]

  \(10\frac{3}{5}\)

• 5]

  \(12\frac{1}{5}\)

5907 – 1296 / 144 = x * 8.0

• 1]

  700.05

• 2]

  705.25

• 3]

  751.54

• 4]

  737.25

If \( \left( {x + \frac{1}{x}} \right){ \text{ = }}\sqrt {13} { \text{,}} \)    then the value of \(\left( {{x^3} - \frac{1}{{{x^3}}}} \right)\)  is = ?

• 1] 26
• 2] 27
• 3] 30
• 4] 36

\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\)   = ?

• 1]

  37/97

• 2]

  74/97

• 3]

  \(1\frac{{23}}{{74}}\)

• 4]

  None of these

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

• 1]

  \(1\frac{1}{8}\)

• 2]

  4/3

• 3]

  15/16

• 4]

  None of these