What will be remainder when (6767 + 67) is divided by 68 ?
67
66
63
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1
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A 3-digit number 4p3 is added to another 3-digit number 984 to give the four-digit number 13q7, which is divisible by 11. Then, (p + q) is :
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2
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If -1 ≤ a ≤ 2 and 1 ≤ b ≤ 3, then least possible value of (2a – 3b) is:
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3
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1397 x 1397 = ?
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4
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(112 X 5^4)
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5
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On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
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6
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3897 X 999
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7
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A number is divided by 221, the remainder is 64. If the number be divided by 13 then the remainder will be
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8
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(?) - 19657 - 33994 = 9999
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9
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476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundred's and ten's places are respectively:
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10
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Find the last unit digit of 55^5 ( Using Euler Theorem)
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