Train X leaves New York at 1 am and travels east at a constant speed of x mph. If train Z leaves New York at 2 am and travels east, at what constant rate of speed will train Z have to travel in order to catch train X at exactly 5.30 am ?
\(\frac{5}{6}x\)
\(\frac{9}{8}x\)
\(\frac{6}{5}x\)
\(\frac{9}{7}x\)
\(\frac{3}{2}x\)
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In a race of 200 meters, B can gives a start of 10 meters to A, and C can gives a start of 20 meters to B. The starts that C can gives to A, in the same race is:
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