The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
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A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
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The ages of A and B are presently in the ratio of 5 : 6 respectively. Six years hence, this ratio became 6 : 7 respectively. What was B's age 5 years ago ?
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The sum of present ages of a father and his son is 8 years more than the present age of the mother. The mother is 22 years older than the son. What will be the age of the father after 4 years?
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The present age of son is half of the present age of his mother. Ten years ago, his mother's age was thrice the age of her son. What is the present age of the son ?
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The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
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The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
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The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
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The present age of Mr. Sanyal is three times the age of his son. Six years hence , the ratio of their ages will be 5 : 2. What is the present age of Mr. Sanyal ?
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The respective ratio between the present age Aarti and Savita is 5 : x. Aartl is 9 years younger than Jahnavi. Jahnavi's age after 9 years will be 33 years. The difference between Savita's and Aarti's age is same as the present age of Jahnavi. What will come in place of x?
SolutionJahnavi's present age= 33 - 9 = 24 years |
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Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages
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