Quiz Discussion

How many rectangles can be formed out of a chess board ?

• 1]

  1740

• 2]

  1230

• 3]

  1296

• 4]

  204

The students in a class are seated, according to their marks in the previous examination. Once, it so happens that four of the students got equal marks and therefore the same rank. To decide their seating arrangement, the teacher wants to write down all possible arrangements one in each of separate bits of paper in order to choose one of these by lots. How many bits of paper are required?

• 1]

  24

• 2]

  12

• 3]

  36

• 4]

  48

How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?

• 1]

  40

• 2]

  400

• 3]

  5040

• 4]

  2520

Find the probability that a leap year selected at random will contain 53 Sundays

• 1]

  2/7

• 2]

  3/7

• 3]

  2/3

• 4]

  5/6

In how many ways can 10 people line up at a ticket window of a railway station?

• 1]

  36,28,800

• 2]

  34,82,800

• 3]

  33,44,800

• 4]

  33,28,800

If a team of 4 persons is to be selected from 8 males and 8 females, then in how many ways can the selections be made to include at least 1 female

• 1]

  3500

• 2]

  1875

• 3]

  1750

• 4]

  3000

How many integers between 1000 and 10000 have no digits other than 4, 5, or 6?

• 1]

  91

• 2]

  71

• 3]

  51

• 4]

  81

A, B, C, D and E sit on five chairs all of which are facing north. C will sit only on the leftmost chair and B will not sit anywhere to the left of A. In how many ways they can be seated?

• 1]

  10

• 2]

  18

• 3]

  36

• 4]

  12

Find the number of ways in which mixed double tennis game can be arranged amongst 9 married couples if no husband and wife play in the same game

• 1]

  1515

• 2]

  1500

• 3]

  1512

• 4]

  1550

Two variants of the CAT paper are to be given to 12 students. In how many ways can the students be placed in two rows of six each so that there should be no identical variants side by side and that the students sitting one behind the other should have the same variant. Find the number of ways this can be done

• 1]

  2 x ¹²C₆ x (6!)²

• 2]

  2 x 6! x 6!

• 3]

  2 x ¹²C₆ x 6!

• 4]

  None of these