Quiz Discussion

\(99 \times 21 - \root 3 \of ? = 1968\)

• 1] 1367631
• 2] 111
• 3] 1366731
• 4] 1367

Which number should replace both the question marks in the following equation ?/1776=111/?

• 1] 343
• 2] 414
• 3] 644
• 4] 543
• 5] None of these

What is \(\frac{{5 + \sqrt {10} }}{{5\sqrt 5 - 2\sqrt {20} - \sqrt {32} + \sqrt {50} }}\)      equal to ?

• 1]

  5

• 2]

  \(5\sqrt 2 \)

• 3]

  \(5\sqrt 5 \)

• 4]

  \(\sqrt 5 \)

If \(a = \frac{{\sqrt 3 + \sqrt 2 }}{{\sqrt 3 - \sqrt 2 }},   b = \frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt 3 + \sqrt 2 }}\)   then the value of \({a^2} + {b^2}\)   would be = ?

• 1] 10
• 2] 98
• 3] 99
• 4] 100

If the product of four consecutive natural numbers increased by a natural number p, is a perfect square, then the value of p is = ?

• 1] 1
• 2] 2
• 3] 4
• 4] 8

The number of digits in the square root of 625685746009 is = ?

• 1] 4
• 2] 5
• 3] 6
• 4] 7

1250 oranges were distributed among a group of girls of a class. Each girl got twice as many oranges as the number of girls in that group. The number of girls in the group was = ?

• 1] 25
• 2] 45
• 3] 50
• 4] 100

Given that \(\sqrt {13} = 3.605\)   and \(\sqrt {130} = 11.40\)  . find the value of \(\sqrt {1.30} \)  + \(\sqrt {1300}\)  + \(\sqrt {0.0130} \)   = ?

• 1] 36.164
• 2] 36.304
• 3] 37.164
• 4] 37.304

\(\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right){\kern 1pt} \)     is equal to :

• 1] 5
• 2] 6
• 3] 8
• 4] 11

What should come in place of both the question marks in the equation x/√128 = √162/x ?

• 1] 12
• 2] 14
• 3] 144
• 4] 196