Quiz Discussion

How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?

Course Name: Quantitative Aptitude

  • 1]

    40

  • 2]

    400

  • 3]

    5040

  • 4]

    2520

Solution
No Solution Present Yet

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# Quiz
1
Discuss

How many natural numbers can be made with digits 0, 7, 8 which are greater than 0 and less than a million?

  • 1]

    496

  • 2]

    728

  • 3]

    486

  • 4]

    1084

Solution
2
Discuss

A coin is tossed 5 times. What is the probability that head appears an odd number of times?

  • 1]

    1/2

  • 2]

    2/3

  • 3]

    1/3

  • 4]

    1

Solution
3
Discuss

How many four-digit numbers, each divisible by 4 can be formed using the digits 5, 6, 7, 8, 9, repetition of digits being allowed in any number?

  • 1]

    75

  • 2]

    100

  • 3]

    125

  • 4]

    150

Solution
4
Discuss

A number lock on a suitcase has 3 wheels each labeled with 10 digits from 0 to 9. If the opening of the lock is a particular sequence of three digits with no repeats, how many such sequences will be possible?

  • 1]

    720

  • 2]

    760

  • 3]

    780

  • 4]

    680

Solution
5
Discuss

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least three men are in the committee. In how many ways can it be done?

  • 1]

    624

  • 2]

    702

  • 3]

    756

  • 4]

    812

Solution
6
Discuss

 

In a single throw with four dice,the probability of throwing seven is

  • 1]

    20/64

  • 2]

    24/65

  • 3]

    22/84

  • 4]

    24/84

Solution
7
Discuss

In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?

  • 1]

    1/10

  • 2]

    2/5

  • 3]

    2/7

  • 4]

    5/7

Solution
8
Discuss

In how many ways can 10 people line up at a ticket window of a railway station?

  • 1]

    36,28,800

  • 2]

    34,82,800

  • 3]

    33,44,800

  • 4]

    33,28,800

Solution
9
Discuss

If P(A)=2/5​, P(B)=3/10​ and P(A ∩ B) =51​, then P(A' | B'). P(B' | A') is equal to

  • 1]

    5/6

  • 2]

    5/7

  • 3]

    25/42

  • 4]

    1

Solution
10
Discuss

There are 6 letters for 3 envelopes. In how many different ways can the envelopes be filled?

  • 1]

    120

  • 2]

    130

  • 3]

    100

  • 4]

    110

Solution
# Quiz