Quiz Discussion

\(\frac{{0.0203 \times 2.92}}{{0.0073 \times 14.5 \times 0.7}} = ?\)

 

Course Name: Quantitative Aptitude

  • 1] 0.8
  • 2] 1.45
  • 3] 2.40
  • 4] 3.25
Solution
No Solution Present Yet

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# Quiz
1
Discuss

\(\frac{{\left( {0.1667} \right)\left( {0.8333} \right)\left( {0.3333} \right)}}{{\left( {0.2222} \right)\left( {0.6667} \right)\left( {0.1250} \right)}}\)     is approximately equal to:

 

  • 1] 2
  • 2] 2.40
  • 3] 2.43
  • 4] 2.50
Solution
2
Discuss

0.002 x 0.5 = ?

  • 1] 0.0001
  • 2] 0.001
  • 3] 0.01
  • 4] 0.1
Solution
3
Discuss

58.621 - 13.829 - 7.302 - 1.214 = ?

  • 1] 31.254
  • 2] 35.272
  • 3] 36.276
  • 4] 37.281
  • 5] None of these
Solution
4
Discuss

The value of \(\left( {\frac{{0.943 \times 0.943 - 0.943 \times 0.057 + 0.057 \times 0.057}}{{0.943 \times 0.943 \times 0.943 + 0.057 \times 0.057 \times 0.057}}} \right)\) is :

 

  • 1] 0.32
  • 2] 0.886
  • 3] 1.1286
  • 4] None of these
Solution
5
Discuss

      is equal to :

 

  • 1]

    1/2

  • 2]

    1/3

  • 3]

    2

  • 4]

    10

Solution
6
Discuss

If 47.2506=4A+7/B+2C+5/D +6E then the value of 5A+3B+6C+D+3E is

  • 1]

    53.6003

  • 2]

    53.603

  • 3]

    153.6003

  • 4]

    213.003

Solution
7
Discuss

When 0.232323..... is converted into a fraction, then the result is:

  • 1]

    1/5

  • 2]

    2/9

  • 3]

    23/99

  • 4]

    23/100

Solution
8
Discuss

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

  • 1]

    2010

  • 2]

    2011

  • 3]

    2012

  • 4]

    2013

Solution
9
Discuss

Solve : \(7\frac{1}{2} -  \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)       = ?

 

  • 1]

    2/9

  • 2]

    \(4\frac{1}{2}\)

  • 3]

    \(9\frac{1}{2}\)

  • 4]

    \(1\frac{77}{228}\)

Solution
10
Discuss

\(\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?\) = ?

 

  • 1] 0.002
  • 2] 0.020
  • 3] 0.021
  • 4] 0.023
Solution
# Quiz