\(\frac{{0.0203 \times 2.92}}{{0.0073 \times 14.5 \times 0.7}} = ?\)
Quiz Recommendation System API Link - https://fresherbell-quiz-api.herokuapp.com/fresherbell_quiz_api
# | Quiz |
---|---|
1
Discuss
|
\(\frac{{\left( {0.1667} \right)\left( {0.8333} \right)\left( {0.3333} \right)}}{{\left( {0.2222} \right)\left( {0.6667} \right)\left( {0.1250} \right)}}\) is approximately equal to:
Solution |
2
Discuss
|
0.002 x 0.5 = ?
Solution |
3
Discuss
|
58.621 - 13.829 - 7.302 - 1.214 = ?
Solution |
4
Discuss
|
The value of \(\left( {\frac{{0.943 \times 0.943 - 0.943 \times 0.057 + 0.057 \times 0.057}}{{0.943 \times 0.943 \times 0.943 + 0.057 \times 0.057 \times 0.057}}} \right)\) is :
Solution |
5
Discuss
|
is equal to :
Solution |
6
Discuss
|
If 47.2506=4A+7/B+2C+5/D +6E then the value of 5A+3B+6C+D+3E is
Solution |
7
Discuss
|
When 0.232323..... is converted into a fraction, then the result is:
Solution |
8
Discuss
|
The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
Solution |
9
Discuss
|
Solve : \(7\frac{1}{2} - \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\) = ?
Solution |
10
Discuss
|
\(\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?\) = ?
Solution |
# | Quiz |
Copyright © 2020 Inovatik - All rights reserved