If \(\left( {x + \frac{1}{x}} \right) = 3,\) then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\) is = ?
10/3
82/9
7
11
Quiz Recommendation System API Link - https://fresherbell-quiz-api.herokuapp.com/fresherbell_quiz_api
# | Quiz |
---|---|
1
Discuss
|
What is the value of \(\frac{{\sqrt {24} + \sqrt {216} }}{{\sqrt {96} }} = ?\)
Solution |
2
Discuss
|
Let 0 < x < 1, then the correct inequality is = ?
Solution |
3
Discuss
|
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?
Solution |
4
Discuss
|
\(\frac{3}{7}{ \text{of }} 455 + \frac{5}{8}{ \text{of}}456 = ?\)
Solution |
5
Discuss
|
5907 – 1296 / 144 = x * 8.0
Solution |
6
Discuss
|
\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)
Solution |
7
Discuss
|
Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
Solution |
8
Discuss
|
If \(\left( {x - \frac{1}{x}} \right){ \text{ = }}\sqrt {21} { \text{,}} \) then the value of \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right) \left( {x + \frac{1}{x}} \right)\) is = ?
Solution |
9
Discuss
|
If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
Solution |
10
Discuss
|
If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\) then 12 + 32 + 52 + . . . . . + 172 is = ?
Solution |
# | Quiz |
Copyright © 2020 Inovatik - All rights reserved