If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\) then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\) is = ?
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The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)
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2
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1559.95 - 7.99 × 24.96 - ?2 = 1154
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3
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The value of \({ \text{3}}\frac{1}{2} - \left[ {2\frac{1}{4} \div \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\) = ?
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4
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If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\) then x = ?
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5
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Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)
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6
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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
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7
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Find the value of \(\sqrt {4 + \sqrt {44 + \sqrt {10000} } } \)
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8
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(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55
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9
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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10
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572.0 / 26 * 12 – 200 = (2)^x
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