Quiz Discussion

If 37/13 =   where x,y,z are natural member , then find x+y+z are:-

Course Name: Python

  • 1]

    6

  • 2]

    7

  • 3]

    8

  • 4]

    9

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)

  • 1]

    10/9

  • 2]

    1/9

  • 3]

    11/7

  • 4]

    8/7

Solution
2
Discuss

Evaluate : \(\frac{{\left( {923 - 347} \right)}}{?} = 32\)

 

  • 1] 35
  • 2] 20
  • 3] 18
  • 4] 15
  • 5] 40
Solution
3
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
4
Discuss

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

 

  • 1]

    0

  • 2]

    1

  • 3]

    \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

  • 4]

    \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)

Solution
5
Discuss

52 + 132  – 112 = (?)3 – 52

  • 1]

    6

  • 2]

    3

  • 3]

    4

  • 4]

    5

Solution
6
Discuss

\(\frac{3}{7}{ \text{of }} 455 + \frac{5}{8}{ \text{of}}456 = ?\)

 

  • 1] 448
  • 2] 464
  • 3] 476
  • 4] 480
  • 5] None of these
Solution
7
Discuss

Simplification of \(\frac{{{{\left( {3.4567} \right)}^2} - {{\left( {3.4533} \right)}^2}}}{{0.0034}} = ?\)

 

  • 1] 6.91
  • 2] 7
  • 3] 6.81
  • 4] 7.1
Solution
8
Discuss

The value of \({ \text{3}}\frac{1}{2} - \left[ {2\frac{1}{4} \div \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)       = ?

 

  • 1]

    1/2

  • 2]

    \(2\frac{1}{2}\)

  • 3]

    \(3\frac{1}{2}\)

  • 4]

    \(9\frac{1}{2}\)

Solution
9
Discuss

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

 

  • 1] 2
  • 2] 8
  • 3] 18
  • 4] None of these
Solution
10
Discuss

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

 

  • 1]

    1

  • 2]

    \(\frac{{x + y + z}}{{a + b + c}}\)

  • 3]

    \(\frac{{a + b + c}}{{x + y + z}}\)

  • 4]

    Not possible to find

Solution
# Quiz