A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?
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Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
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The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\) is = ?
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421 ÷ 35 × 299.97 ÷ 25.05 = ?2
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The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?
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\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\) Find the value in place of (?)
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98643 – 21748 = 51212 + ?
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\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\) is equal to ?
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If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?
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The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?
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853 + ? / 17 = 1000
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