Quiz Discussion

Let 0 < x < 1, then the correct inequality is = ?

• 1]

  \(x < \sqrt x < {x^2}\)

• 2]

  \(\sqrt x < x < {x^2}\)

• 3]

  \({x^2} < x < \sqrt x \)

• 4]

  \(\sqrt x < {x^2} < x\)

\(\frac{{{{\left( {a - b} \right)}^2} - {{\left( {a + b} \right)}^2}}}{{ - 4a}}{ \text{ = }}\frac{x}{y}\)     On simplifying the given equations, which of the following equations will be obtained ?

• 1] xy = b
• 2] bx = y
• 3] ab = x
• 4] yb = x
• 5] ay = x

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

\(6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?\)

• 1]

  \(112\frac{1}{3}\)

• 2]

  \(116\frac{2}{3}\)

• 3]

  240

• 4]

  663

• 5]

  None of these

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

• 1] 770
• 2] 1155
• 3] 1540
• 4] (385)2

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

( √5 – 2)^2 = x – √80

• 1]

  9

• 2]

  7

• 3]

  6

• 4]

  10

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

If a*b= ab/a+b, find the value of 3*(3*-1)

• 1]

  -1

• 2]

  1

• 3]

  3

• 4]

  -3

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these