Quiz Discussion

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

• 1]

  7

• 2]

  \(1\frac{3}{4}\)

• 3]

  \(\frac{7}{{1000}}\)

• 4]

  \(\frac{4}{7}\)

853 + ? / 17 = 1000

• 1] 2482
• 2] 2499
• 3] 2516
• 4] 16147
• 5] None of these

421 ÷ 35 × 299.97 ÷ 25.05 = ?2

• 1] 22
• 2] 24
• 3] 28
• 4] 12
• 5] 18

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\)   = ?

• 1]

  37/97

• 2]

  74/97

• 3]

  \(1\frac{{23}}{{74}}\)

• 4]

  None of these

( √5 – 2)^2 = x – √80

• 1]

  9

• 2]

  7

• 3]

  6

• 4]

  10

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

• 1] 969
• 2] 1785
• 3] 980
• 4] 1700

Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)

• 1]

  0.006

• 2]

  1/6

• 3]

  0.6

• 4]

  6

\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)

• 1] 0.1
• 2] 10
• 3] 102
• 4] 103