Quiz Discussion

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

Solve : 128.43 + 30.21 + ? = 173

• 1] 35.66
• 2] 29.66
• 3] 43.66
• 4] 24.66
• 5] 14.36

The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?

• 1] 27
• 2] 18
• 3] 40
• 4] 10

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

• 1]

  \(1\frac{{11}}{{17}}\)

• 2]

  \(1\frac{{5}}{{7}}\)

• 3]

  \(1\frac{{6}}{{17}}\)

• 4]

  \(1\frac{{21}}{{17}}\)

4848 / 24 * 11 - 222 = ?

• 1]

  200

• 2]

  2444

• 3]

  2000

• 4]

  \(115\frac{3}{8}\)

If \( \left( {x + \frac{1}{x}} \right){ \text{ = }}\sqrt {13} { \text{,}} \)    then the value of \(\left( {{x^3} - \frac{1}{{{x^3}}}} \right)\)  is = ?

• 1] 26
• 2] 27
• 3] 30
• 4] 36

If \(\frac{a}{b}{ \text{ + }}\frac{b}{a}{ \text{ = 2,}}\)    then the value of (a - b) is = ?

• 1] 1
• 2] 2
• 3] -1
• 4] 0

Find the value of \(\sqrt {248 + \sqrt {52 + \sqrt {144} } } = ?\)

• 1]

  -16

• 2]

  \(\pm 16\)

• 3]

  16

• 4]

  16.2

\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\)      = ?

• 1] 0.27
• 2] 0.4087
• 3] 0.73
• 4] 1