A sum of Rs. 1360 has been divided among A, B and C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. B's share is:
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1
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\(1888 \div 32 \div 8 = ?\)
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2
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(? - 968) / 79 * 4 = 512
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3
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The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)
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4
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If \(\left( {x + \frac{1}{x}} \right) = 3,\) then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\) is = ?
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5
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If a*b= ab/a+b, find the value of 3*(3*-1)
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6
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5907 – 1296 / 144 = x * 8.0
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7
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3/5 of 4/7 of 5/9 of 21/24 of 504 = ?
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8
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\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)
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9
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Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)
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10
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64^12 / 4^15 = 64^x
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