200 ÷ 25 × 4 + 12 - 3 = ?
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1
Discuss
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The least number that must be subtracted from 63522 to make the result a perfect square is = ?
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2
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Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times 2\sqrt {3\frac{1}{9}}\) = ?
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3
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64^12 / 4^15 = 64^x
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4
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\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\) is equal to = ?
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5
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If \(\left( {x + \frac{1}{x}} \right) = 3,\) then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\) is = ?
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6
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On simplification the value of \({ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }} \frac{1}{{1 - \sqrt 2 }}\) is = ?
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7
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The value of \(\frac{{25 - 5\left[ {2 + 3\left\{ {2 - 2\left( {5 - 3} \right) + 5} \right\} - 10} \right]}}{4} = ?\)
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8
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If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\) then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\) is = ?
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9
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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10
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\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\) is equal to = ?
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