Quiz Discussion

200 ÷ 25 × 4 + 12 - 3 = ?

Course Name: Java

  • 1] 35
  • 2] 40
  • 3] 30
  • 4] 41
  • 5] 50
Solution
No Solution Present Yet

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# Quiz
1
Discuss

The least number that must be subtracted from 63522 to make the result a perfect square is = ?

  • 1] 18
  • 2] 20
  • 3] 24
  • 4] 30
Solution
2
Discuss

Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times  2\sqrt {3\frac{1}{9}}\)   = ?

 

  • 1]

    45/256

  • 2]

    \(1\frac{{17}}{{28}}\)

  • 3]

    \(4\frac{3}{8}\)

  • 4]

    \(2\frac{3}{{16}}\)

Solution
3
Discuss

64^12 / 4^15 = 64^x

  • 1]

    6

  • 2]

    5

  • 3]

    4

  • 4]

    7

Solution
4
Discuss

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

 

  • 1] 24
  • 2] 32
  • 3] 44
  • 4] 100
Solution
5
Discuss

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

 

  • 1]

    10/3

  • 2]

    82/9

  • 3]

    7

  • 4]

    11

Solution
6
Discuss

On simplification the value of \({ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }}  \frac{1}{{1 - \sqrt 2 }}\)  is = ?

 

  • 1]

    \(2\sqrt 2 - 1\)

  • 2]

    \(1 - 2\sqrt 2 \)

  • 3]

    \(1 - \sqrt 2 \)

  • 4]

    \( - 2\sqrt 2 \)

Solution
7
Discuss

The value of \(\frac{{25 - 5\left[ {2 + 3\left\{ {2 - 2\left( {5 - 3} \right) + 5} \right\} - 10} \right]}}{4} = ?\)

 

  • 1] 5
  • 2] 23.25
  • 3] 23.75
  • 4] 25
Solution
8
Discuss

If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\)     then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\)   is = ?

 

  • 1] 198
  • 2] 200
  • 3] 216
  • 4] None of these
Solution
9
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
10
Discuss

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

 

  • 1] a - b
  • 2] b - a
  • 3] 1
  • 4] 0
Solution
# Quiz