Quiz Discussion

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

• 1]

  5/16

• 2]

  6/19

• 3]

  18/5

• 4]

  24/11

\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)

• 1]

  2/5

• 2]

  5/2

• 3]

  3/5

• 4]

  1/2

Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)

• 1] 4
• 2] 3
• 3] 2
• 4] 1

The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)

• 1]

  5

• 2]

  5/3

• 3]

  5/12

• 4]

  3/4

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

• 1] ± 2
• 2] 1, 2
• 3] 2, 3
• 4] ± 1

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

\(\sqrt {0.00060516} \)     is equal to = ?

• 1] 0.0246
• 2] 0.00246
• 3] 0.246
• 4] 0.000246

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

• 1] 24
• 2] 32
• 3] 44
• 4] 100