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Quiz Discussion

If a - b = 3 and a2 + b2 = 29, find the value of ab = ?

Course Name: Quantitative Aptitude

1] 10
2] 12
3] 15
4] 18

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1 Discuss	$\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}$ = ? 1] 0.27 2] 0.4087 3] 0.73 4] 1 Solution
10 Discuss	(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55 1] 2254 2] 2354 3] 2368 4] 2404 5] None of these Solution
2 Discuss	1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to: 1] -4 2] 2 3] 0 4] 2 Solution
3 Discuss	If $\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}$ then $\left( {x - \frac{1}{x}} \right)$ is equal to = ? 1] 0 2] 1 3] 2 4] 5 Solution
4 Discuss	There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is: 1] 20 2] 80 3] 100 4] 200 5] None of these Solution
5 Discuss	If $\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}$ and $\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}}$ then the value of $\frac{{x - y}}{{1 + xy}}$ = ? 1] $\frac{{2ab}}{{{a^2} - {b^2}}}$ 2] $\frac{{{a^2} - {b^2}}}{{2ab}}$ 3] $\frac{{{a^2} + {b^2}}}{{2ab}}$ 4] $\frac{{{a^2} - {b^2}}}{{ab}}$ Solution
6 Discuss	On simplification the value of ${ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }} \frac{1}{{1 - \sqrt 2 }}$ is = ? 1] $2\sqrt 2 - 1$ 2] $1 - 2\sqrt 2$ 3] $1 - \sqrt 2$ 4] $- 2\sqrt 2$ Solution
7 Discuss	Solve 4376 + 3209 - 1784 + 97 = 3125 + ? 1] 2713 2] 2743 3] 2773 4] 2793 5] 2737 Solution
8 Discuss	Simplify : ${ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]$ 1] $4\frac{1}{2}$ 2] $4\frac{1}{6}$ 3] $9\frac{1}{2}$ 4] $\frac{2}{9}$ Solution
9 Discuss	Find the value of $\sqrt {248 + \sqrt {52 + \sqrt {144} } } = ?$ 1] -16 2] $\pm 16$ 3] 16 4] 16.2 Solution
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