Quiz Discussion

( √5 – 2)^2 = x – √80

• 1]

  9

• 2]

  7

• 3]

  6

• 4]

  10

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

• 1] 24
• 2] 32
• 3] 44
• 4] 100

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

What is the value of \(\frac{{\sqrt {24} + \sqrt {216} }}{{\sqrt {96} }} = ?\)

• 1]

  \(2\sqrt 6\)

• 2]

  \(4\sqrt 6 \)

• 3]

  2

• 4]

  4

The value of \(\frac{5}{{1\frac{7}{8}{ \text{of 1}}\frac{1}{3}}} \times \frac{{2\frac{1}{{10}}}}{{3\frac{1}{2}}}{ \text{ of 1}}\frac{1}{4} = ?\)

• 1]

  \(1\frac{1}{2}\)

• 2]

  0.05

• 3]

  1

• 4]

  2

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

5907 – 1296 / 144 = x * 8.0

• 1]

  700.05

• 2]

  705.25

• 3]

  751.54

• 4]

  737.25

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?

• 1]

  5.5

• 2]

  4.0

• 3]

  4.5

• 4]

  3.0

The value of \(\frac{{25 - 5\left[ {2 + 3\left\{ {2 - 2\left( {5 - 3} \right) + 5} \right\} - 10} \right]}}{4} = ?\)

• 1] 5
• 2] 23.25
• 3] 23.75
• 4] 25