The simplified value of
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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
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Evaluate : \({{ - {{\left( {4 - 6} \right)}^2} - 3\left( { - 2} \right) + \left| { - 6} \right|} \over {18 - 9 \div 3 \times 5}}\)
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3
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1559.95 - 7.99 × 24.96 - ?2 = 1154
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Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)
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Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\) = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\) + \(\sqrt {0.013}\)
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A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?
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If the sum of two numbers is 22 and the sum of their squares is 404, then the product of two numbers is = ?
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8
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\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\) be a perfect square, then the values of t are = ?
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9
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\(\left( {\frac{{785 \times 785 \times 785 + 435 \times 435 \times 435}}{{785 \times 785 + 435 \times 435 - 785 \times 435}}} \right)\) simplifies to = ?
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421 ÷ 35 × 299.97 ÷ 25.05 = ?2
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