Quiz Discussion

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

• 1] ± 2
• 2] 1, 2
• 3] 2, 3
• 4] ± 1

To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?

• 1] 10
• 2] 35
• 3] 62.5
• 4] Cannot be determined
• 5] None of these

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

• 1]

  7

• 2]

  \(1\frac{3}{4}\)

• 3]

  \(\frac{7}{{1000}}\)

• 4]

  \(\frac{4}{7}\)

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

• 1]

  5/16

• 2]

  6/19

• 3]

  18/5

• 4]

  24/11

The expression \(\frac{1}{{x - 1}} - \frac{1}{{x + 1}} - \frac{2}{{{x^2} + 1}} - \frac{4}{{{x^4} + 1}}\)  is equal to = ?

• 1]

  \(\frac{8}{{{x^8} + 1}}\)

• 2]

  \(\frac{8}{{{x^8} - 1}}\)

• 3]

  \(\frac{8}{{{x^7} - 1}}\)

• 4]

  \(\frac{8}{{{x^7} + 1}}\)

On simplification the value of \({ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }}  \frac{1}{{1 - \sqrt 2 }}\)  is = ?

• 1]

  \(2\sqrt 2 - 1\)

• 2]

  \(1 - 2\sqrt 2 \)

• 3]

  \(1 - \sqrt 2 \)

• 4]

  \( - 2\sqrt 2 \)

What is the value of \(\frac{{\sqrt {24} + \sqrt {216} }}{{\sqrt {96} }} = ?\)

• 1]

  \(2\sqrt 6\)

• 2]

  \(4\sqrt 6 \)

• 3]

  2

• 4]

  4

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

• 1]

  \(1\frac{1}{8}\)

• 2]

  4/3

• 3]

  15/16

• 4]

  None of these