Quiz Discussion

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

Course Name: Quantitative Aptitude

  • 1] 3, 1
  • 2] 3, 3
  • 3] 4, 1
  • 4] 5, 3
Solution
No Solution Present Yet

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# Quiz
1
Discuss

Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)

 

  • 1]

    0.006

  • 2]

    1/6

  • 3]

    0.6

  • 4]

    6

Solution
2
Discuss

Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)

 

  • 1]

    \(4\frac{1}{2}\)

  • 2]

    \(4\frac{1}{6}\)

  • 3]

    \(9\frac{1}{2}\)

  • 4]

    \(\frac{2}{9}\)

Solution
3
Discuss

Simplify : \(\frac{{\frac{5}{3} \times \frac{7}{{51}}{ \text{ of }}\frac{17}{5} - \frac{1}{3}}}{{\frac{2}{9} \times \frac{5}{7}{ \text{ of }}\frac{{28}}{5} - \frac{2}{3}}}{\kern 1pt} {\kern 1pt} = ?\)

 

  • 1]

    1/3

  • 2]

    1/6

  • 3]

    4

  • 4]

    2

Solution
4
Discuss

52 + 132  – 112 = (?)3 – 52

  • 1]

    6

  • 2]

    3

  • 3]

    4

  • 4]

    5

Solution
5
Discuss

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

  • 1] a
  • 2] b
  • 3] c
  • 4] All equal
Solution
6
Discuss

5 - [4 - {3 - (3 - 3 - 6)}] is equal to:

  • 1] 10
  • 2] 6
  • 3] 4
  • 4] 0
Solution
7
Discuss

Simplify : \(\root 3 \of { - 2197} \,\times \)  \(\root 3 \of { - 125} \,\,\div \)   \(\root 3 \of {\frac{{27}}{{512}}} \)  = ?

 

  • 1]

    \(\frac{{492}}{7}\)

  • 2]

    \(\frac{{520}}{3}\)

  • 3]

    \(\frac{{554}}{7}\)

  • 4]

    \(\frac{{571}}{5}\)

Solution
8
Discuss

\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)

 

  • 1]

    \(2\frac{7}{{40}}\)

  • 2]

    \(3\frac{7}{{40}}\)

  • 3]

    \(9\frac{5}{8}\)

  • 4]

    \(10\frac{7}{8}\)

  • 5]

    None of these

Solution
9
Discuss

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

  • 1]

    3ad

  • 2]

    3ac

  • 3]

    2ad

  • 4]

    2ab

Solution
10
Discuss

(4 / 5) × ? × (3 / 7) = (16 / 105)

  • 1]

    8/9

  • 2]

    5/7

  • 3]

    4/9

  • 4]

    3/7

Solution
# Quiz