Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
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1
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Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)
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2
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Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)
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3
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Simplify : \(\frac{{\frac{5}{3} \times \frac{7}{{51}}{ \text{ of }}\frac{17}{5} - \frac{1}{3}}}{{\frac{2}{9} \times \frac{5}{7}{ \text{ of }}\frac{{28}}{5} - \frac{2}{3}}}{\kern 1pt} {\kern 1pt} = ?\)
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4
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52 + 132 – 112 = (?)3 – 52
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5
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Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?
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6
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5 - [4 - {3 - (3 - 3 - 6)}] is equal to:
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7
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Simplify : \(\root 3 \of { - 2197} \,\times \) \(\root 3 \of { - 125} \,\,\div \) \(\root 3 \of {\frac{{27}}{{512}}} \) = ?
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8
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\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)
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9
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If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?
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10
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(4 / 5) × ? × (3 / 7) = (16 / 105)
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