Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?
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If \(\left( {a + \frac{1}{a}} \right) = 6, then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\) = ?
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Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\) = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\) + \(\sqrt {0.013}\)
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( √5 – 2)^2 = x – √80
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\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\) is equal to = ?
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\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\) \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
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If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \) then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\) = ?
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If the expression \({ \text{2}}\frac{1}{2}{ \text{ of }}\frac{3}{4} \times \frac{1}{2} \div \frac{3}{2} + \frac{1}{2} \div \frac{3}{2}\left[ {\frac{2}{3} - \frac{1}{2}{ \text{ of }}\frac{2}{3}} \right]\) is simplified, we get -
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Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
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If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?
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Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)
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