Quiz Discussion

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

 

Course Name: Quantitative Aptitude

  • 1]

    6/49

  • 2]

    6/11

  • 3]

    3/28

  • 4]

    1/7

  • 5]

    None of these

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)

  • 1]

    10/9

  • 2]

    1/9

  • 3]

    11/7

  • 4]

    8/7

Solution
2
Discuss

Find the value of \(\sqrt {248 + \sqrt {52 + \sqrt {144} } } = ?\)

 

  • 1]

    -16

  • 2]

    \(\pm 16\)

  • 3]

    16

  • 4]

    16.2

Solution
3
Discuss

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

 

  • 1]

    \({x^6} - \frac{1}{{{x^6}}}\)

  • 2]

    \({x^8} - \frac{1}{{{x^8}}}\)

  • 3]

    \({x^6} + \frac{1}{{{x^6}}}\)

  • 4]

    \({x^8} + \frac{1}{{{x^8}}}\)

Solution
4
Discuss

\(1888 \div 32 \div 8 = ?\)

 

  • 1] 7.375
  • 2] 9.485
  • 3] 29.5
  • 4] 472
  • 5] None of these
Solution
5
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
6
Discuss

Simplification of \(\frac{{{{\left( {3.4567} \right)}^2} - {{\left( {3.4533} \right)}^2}}}{{0.0034}} = ?\)

 

  • 1] 6.91
  • 2] 7
  • 3] 6.81
  • 4] 7.1
Solution
7
Discuss

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

  • 1] -4
  • 2] 2
  • 3] 0
  • 4] 2
Solution
8
Discuss

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

 

  • 1] -1
  • 2] 0
  • 3] 1
  • 4] None of these
Solution
9
Discuss

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

  • 1]

    3ad

  • 2]

    3ac

  • 3]

    2ad

  • 4]

    2ab

Solution
10
Discuss

The value of x in the equation  = 5     is?

 

  • 1] 21
  • 2] 27
  • 3] 35
  • 4] 42
Solution
# Quiz