Quiz Discussion

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

Course Name: Quantitative Aptitude

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
No Solution Present Yet

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# Quiz
1
Discuss

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

 

  • 1] 1
  • 2] 4
  • 3] 3
  • 4] 2
Solution
2
Discuss

Simplify : \(1 + {2 \over {1 + {3 \over {1 + {4 \over 5}}}}}\)

 

  • 1]

    7/4

  • 2]

    4/7

  • 3]

    7/5

  • 4]

    3/7

Solution
3
Discuss

Simplify : \(\frac{{ - \frac{1}{2} - \frac{2}{3} + \frac{4}{5} - \frac{1}{3} + \frac{1}{5} + \frac{3}{4}}}{{\frac{1}{2} + \frac{2}{3} - \frac{4}{3} + \frac{1}{3} - \frac{1}{5} - \frac{4}{5}}}\)

 

  • 1]

    -3/10

  • 2]

    -10/3

  • 3]

    -2

  • 4]

    1

Solution
4
Discuss

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

 

  • 1] a - b
  • 2] b - a
  • 3] 1
  • 4] 0
Solution
5
Discuss

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

 

  • 1]

    1

  • 2]

    \(\frac{{x + y + z}}{{a + b + c}}\)

  • 3]

    \(\frac{{a + b + c}}{{x + y + z}}\)

  • 4]

    Not possible to find

Solution
6
Discuss

If \(\root 3 \of {{3^n}} { \text{ = 27,}}\)  then the value of n is = ?

 

  • 1] 9
  • 2] 6
  • 3] 1
  • 4] 3
Solution
7
Discuss

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

 

  • 1]

    \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

  • 2]

    \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

  • 3]

    \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

  • 4]

    \(\frac{{{a^2} - {b^2}}}{{ab}}\)

Solution
8
Discuss

Simplify : \(1 - \left[ {1 - \left\{ {1 - \left( {1 - \overline {1 - 1} } \right)} \right\}} \right]\)

 

  • 1] 0
  • 2] 1
  • 3] 2
  • 4] 3
  • 5] None of these
Solution
9
Discuss

On simplification the value of \({ \text{1}} - \frac{1}{{1 + \sqrt 2 }}{ \text{ + }}  \frac{1}{{1 - \sqrt 2 }}\)  is = ?

 

  • 1]

    \(2\sqrt 2 - 1\)

  • 2]

    \(1 - 2\sqrt 2 \)

  • 3]

    \(1 - \sqrt 2 \)

  • 4]

    \( - 2\sqrt 2 \)

Solution
10
Discuss

\(6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?\)

 

  • 1]

    \(112\frac{1}{3}\)

  • 2]

    \(116\frac{2}{3}\)

  • 3]

    240

  • 4]

    663

  • 5]

    None of these

Solution
# Quiz