Quiz Discussion

A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

• 1] 45
• 2] 60
• 3] 75
• 4] 90
• 5] None of these

Solve this 9 3/7 - 6 4/7 - ? = 14 4/7

• 1]

  3/7

• 2]

  4/7

• 3]

  

• 4]

  

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)

• 1]

  100/101

• 2]

  90/101

• 3]

  20/101

• 4]

  101/100

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

• 1]

  40.019

• 2]

  35.055

• 3]

  37.514

• 4]

  38.399

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

• 1] 2713
• 2] 2743
• 3] 2773
• 4] 2793
• 5] 2737

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

• 1] -1
• 2] 0
• 3] 1
• 4] None of these

If a - b = 3 and a2 + b2 = 29, find the value of ab = ?

• 1] 10
• 2] 12
• 3] 15
• 4] 18

Evaluate : \({{ - {{\left( {4 - 6} \right)}^2} - 3\left( { - 2} \right) + \left| { - 6} \right|} \over {18 - 9 \div 3 \times 5}}\)

• 1]

  \(\frac{3}{8}\)

• 2]

  \(\frac{4}{7}\)

• 3]

  \(\frac{8}{3}\)

• 4]

  \(\frac{7}{4}\)