Quiz Discussion

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

• 1] 5√5
• 2] (125)2
• 3] 25
• 4] 5
• 5] None of these

5907 – 1296 / 144 = x * 8.0

• 1]

  700.05

• 2]

  705.25

• 3]

  751.54

• 4]

  737.25

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

• 1] 1
• 2] 4
• 3] 295
• 4] 643

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

If \(\left( {a + \frac{1}{a}} \right) = 6,    then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\)   = ?

• 1] 1154
• 2] 1158
• 3] 1160
• 4] 1164

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

572.0 / 26 * 12 – 200 = (2)^x

• 1]

  8

• 2]

  4

• 3]

  6

• 4]

  10

If x + y = 2a, then the value of

• 1] 2
• 2] 0
• 3] -1
• 4] 1

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these