Quiz Discussion

If a + 1, 2a + 1, 4a - 1 are in A.P., then the value of a is:

 

Course Name: Quantitative Aptitude

  • 1]

    1

  • 2]

    2

  • 3]

    3

  • 4]

    4

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If three numbers be in G.P., then their logarithms will be in

  • 1]

    AP

  • 2]

    GP

  • 3]

    HP

  • 4]

     None Of This

Solution
2
Discuss

The first term of an Arithmetic Progression is 22 and the last term is -11. If the sum is 66, the number of terms in the sequence are:

  • 1]

    9

  • 2]

    10

  • 3]

    11

  • 4]

    12

Solution
3
Discuss

If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is

 

  • 1]

    -2

  • 2]

    -3

  • 3]

    2

  • 4]

    3

Solution
4
Discuss

If a + 1, 2a + 1, 4a - 1 are in A.P., then the value of a is:

  • 1] 1
  • 2] 2
  • 3] 3
  • 4] 4
Solution
5
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(\frac{{n\left( {n - 1} \right)}}{2}\)

  • 3]

    \({n^2}\)

  • 4]

    n

Solution
6
Discuss

What is the sum of the first 11 terms of an arithmetic progression if the 3rd term is -1 and the 8th term is 19?

  • 1] 204
  • 2] 121
  • 3] 225
  • 4] 104
Solution
7
Discuss

15th term of A.P., x - 7, x - 2, x + 3, ........ is

  • 1] x + 63
  • 2] x + 73
  • 3] x + 83
  • 4] x + 53
Solution
8
Discuss

Sum of n terms of the series \(\sqrt 2   +   \sqrt 8   +   \sqrt {18}   +   \sqrt {32}   +  \) ....... is

 

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(2n\left( {n + 1} \right)\)

  • 3]

    \(\frac{{n\left( {n + 1} \right)}}{{\sqrt 2 }}\)

  • 4]

    1

Solution
9
Discuss

If the sum of n terms of an A.P. be 3n2 + n and its common difference is 6, then its first term is

  • 1] 2
  • 2] 3
  • 3] 1
  • 4] 4
Solution
10
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
# Quiz