Processing math: 100%

Back to Top

Quiz Discussion

Given that =3.605 and =11.40 , Find the value of + +

Course Name: Quantitative Aptitude

1]
36.164
2]
36.304
3]
37.164
4]
37.304

Solution

No Solution Present Yet

Top 5 Similar Quiz - Based On AI&ML

Quiz Recommendation System API Link - https://fresherbell-quiz-api.herokuapp.com/fresherbell_quiz_api

Show entries

Search:

#	Quiz
1 Discuss	$6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?$ 1] $112\frac{1}{3}$ 2] $116\frac{2}{3}$ 3] 240 4] 663 5] None of these Solution
10 Discuss	(4/9) × 1701 + (2/11) × 1386 = ? 1] 180 2] 1080 3] 1008 4] 1800 Solution
2 Discuss	If $\left( {x + \frac{1}{x}} \right){ \text{ = }}\sqrt {13} { \text{,}}$ then the value of $\left( {{x^3} - \frac{1}{{{x^3}}}} \right)$ is = ? 1] 26 2] 27 3] 30 4] 36 Solution
3 Discuss	$\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}$ Find the value in place of (?) 1] 2 2] 8 3] 18 4] None of these Solution
4 Discuss	If 547.527/0.0082 then the value of 547527/82 is = ? 1] 10x 2] 100x 3] x/100 4] x/10 Solution
5 Discuss	Simplify : $\frac{{ - \frac{1}{2} - \frac{2}{3} + \frac{4}{5} - \frac{1}{3} + \frac{1}{5} + \frac{3}{4}}}{{\frac{1}{2} + \frac{2}{3} - \frac{4}{3} + \frac{1}{3} - \frac{1}{5} - \frac{4}{5}}}$ 1] -3/10 2] -10/3 3] -2 4] 1 Solution
6 Discuss	3/5 of 4/7 of 5/9 of 21/24 of 504 = ? 1] 63 2] 39 3] 96 4] 84 Solution
7 Discuss	If $\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}$ and $\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}}$ then the value of $\frac{{x - y}}{{1 + xy}}$ = ? 1] $\frac{{2ab}}{{{a^2} - {b^2}}}$ 2] $\frac{{{a^2} - {b^2}}}{{2ab}}$ 3] $\frac{{{a^2} + {b^2}}}{{2ab}}$ 4] $\frac{{{a^2} - {b^2}}}{{ab}}$ Solution
8 Discuss	If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ? 1] 0 2] 6xyz 3] 12xyz 4] xyz Solution
9 Discuss	Simplify : ${{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}$ 1] 1/2 2] 4 3] 2 4] 1/4 Solution
#	Quiz

Showing 1 to 10 of 10 entries

Social Media

Copyright © 2020 Inovatik - All rights reserved