Anna left for city A from city B at 5.20 am. She travelled at the speed of 80 km/hr for 2 hours 15 minutes. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach reach city A ?
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A man travels 600 km by train at 80 km/hr, 800 km by ship at 40 km/hr, 500 km by aeroplane at 400 km/hr and 100 km by car at 50 km/hr. What is the average speed for the entire distance :
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A dog after traveling 50 km meets a swami who counsels him to go slower. He then proceeds at \(\frac{3}{4} \)of his former speed and arrives at his destination 35 min late. Had the meeting occurred 24 km further the dog would have reached its destination 25 min late. The speed of the dog is:
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A plan left 40 minutes late due to bad whether and order to reach its destination 1600 km away in time, it had increase its speed by 400 kmph from its usual speed. Find the usual speed of the plane?
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A train travels at a speed of 30 km/hr for 12 minutes and at a speed of 45 km/hr for the next 8 minutes. The average speed of the train for this journey is :
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Walking \({\frac{6}{7}}\) th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is :
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A man walking at the rate of 5 km/hr crosses a bridge in 15 min. The length of the bridge (in metres) is :
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A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/hr, the time taken by it to cover the same distance will be :
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Two boys A and B start at the same time to ride from Delhi to Meerut, 60 km away. A travels 4 km an hours slower than B, B reaches Meerut and at once turns back meeting A, 12 km from Meerut. A's rate was :
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A man can walk uphill at the rate of \(2\frac{1}{2}\) km/hr and downhill at the rate of \(3\frac{1}{4}\) km/hr. If the total time required to walk a certain distance up the hill and return to the starting point was 4 hr 36 min, then what was the distance walked up the hill by the man ?
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A bullock cart has to cover a distance of 120 km in 15 hours. If it covers half of the journey in \(\frac{3}{5}\)th time, the second to cover the remaining distance in the time left has to be :
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